What are the solutions to the equation 8k^2+16k-25=-2 ?

The solutions to the equation 8k^2+16k-25=-2 are k=(-4+sqrt(62))/4 ,k=-(4+sqrt(62))/4

Find the zeros of 8k^2+16k-25=-2

The zeros of 8k^2+16k-25=-2 are k=(-4+sqrt(62))/4 ,k=-(4+sqrt(62))/4

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8 k^{2} + 16 k - 25 = - 2

k = \frac{- 4 + 62}{4}, k = - \frac{4 + 62}{4}

Solution steps

8 k^{2} + 16 k - 25 = - 2

Move

2

to the left side

8 k^{2} + 16 k - 23 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 8 ( - 23 )}{2 \cdot 8}

1 6^{2} - 4 \cdot 8 (- 23) = 462

k_{1, 2} = \frac{- 16 \pm 4 62}{2 \cdot 8}

Separate the solutions

k_{1} = \frac{- 16 + 4 62}{2 \cdot 8}, k_{2} = \frac{- 16 - 4 62}{2 \cdot 8}

k = \frac{- 16 + 4 62}{2 \cdot 8} : \frac{- 4 + 62}{4}

k = \frac{- 16 - 4 62}{2 \cdot 8} : - \frac{4 + 62}{4}

The solutions to the quadratic equation are:

k = \frac{- 4 + 62}{4}, k = - \frac{4 + 62}{4}

(6 + 7 i)^{2}

49 x^{2} + 28 x y + 4 y^{2}

16 x^{2} - 16 x + 5 = 0

- 61 - 15 x = 1 - 20 x + 38

6 (x - 9) = 18

What are the solutions to the equation 8k^2+16k-25=-2 ?
The solutions to the equation 8k^2+16k-25=-2 are k=(-4+sqrt(62))/4 ,k=-(4+sqrt(62))/4
Find the zeros of 8k^2+16k-25=-2
The zeros of 8k^2+16k-25=-2 are k=(-4+sqrt(62))/4 ,k=-(4+sqrt(62))/4