What are the solutions to the equation (x+1)^2+1=0 ?

The solutions to the equation (x+1)^2+1=0 are x=i-1,x=-i-1

Find the zeros of (x+1)^2+1=0

The zeros of (x+1)^2+1=0 are x=i-1,x=-i-1

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(x + 1)^{2} + 1 = 0

x = i - 1, x = - i - 1

Solution steps

(x + 1)^{2} + 1 = 0

Move

1

to the right side

(x + 1)^{2} = - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = - 1 : x = i - 1

Solve

x + 1 = - - 1 : x = - i - 1

The solutions to the quadratic equation are:

x = i - 1, x = - i - 1

\frac{- 8 Q ^{2} + 20 Q + 800}{189} = 0

- \frac{7}{8} x = - 5

11 - 2 ∣ x + 4 ∣ > 8

6 x^{5} - 48 x^{2}

3 (x + 4) > 21

What are the solutions to the equation (x+1)^2+1=0 ?
The solutions to the equation (x+1)^2+1=0 are x=i-1,x=-i-1
Find the zeros of (x+1)^2+1=0
The zeros of (x+1)^2+1=0 are x=i-1,x=-i-1