What are the solutions to the equation 0=16x^2-59x-20 ?

The solutions to the equation 0=16x^2-59x-20 are x=4,x=-5/16

Find the zeros of 0=16x^2-59x-20

The zeros of 0=16x^2-59x-20 are x=4,x=-5/16

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0 = 16 x^{2} - 59 x - 20

x = 4, x = - \frac{5}{16}

Decimal Notation

x = 4, x = - 0.3125

Solution steps

0 = 16 x^{2} - 59 x - 20

Switch sides

16 x^{2} - 59 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 59 ) \pm ( - 59 ) ^{2} - 4 \cdot 16 ( - 20 )}{2 \cdot 16}

(- 59)^{2} - 4 \cdot 16 (- 20) = 69

x_{1, 2} = \frac{- ( - 59 ) \pm 69}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 59 ) + 69}{2 \cdot 16}, x_{2} = \frac{- ( - 59 ) - 69}{2 \cdot 16}

x = \frac{- ( - 59 ) + 69}{2 \cdot 16} : 4

x = \frac{- ( - 59 ) - 69}{2 \cdot 16} : - \frac{5}{16}

The solutions to the quadratic equation are:

x = 4, x = - \frac{5}{16}

x^{2} + 3 x = 6

(4)^{\frac{2}{3}}

6 x^{2} + 4 = 25 x

2 (x^{2} - 2) < 3 (x - 3) - x^{2}

x^{10} - y^{10}

What are the solutions to the equation 0=16x^2-59x-20 ?
The solutions to the equation 0=16x^2-59x-20 are x=4,x=-5/16
Find the zeros of 0=16x^2-59x-20
The zeros of 0=16x^2-59x-20 are x=4,x=-5/16