What is the answer to solvefor d,sqrt(1/2 y-1)= 3/4 y+d ?

The answer to solvefor d,sqrt(1/2 y-1)= 3/4 y+d is d=sqrt((y-2)/2)-3/4 y

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solvefor d,sqrt(1/2 y-1)= 3/4 y+d

solve for

d, \frac{1}{2} y - 1 = \frac{3}{4} y + d

d = \frac{y - 2}{2} - \frac{3}{4} y

Solution steps

\frac{1}{2} y - 1 = \frac{3}{4} y + d

Switch sides

\frac{3}{4} y + d = \frac{1}{2} y - 1

Move

\frac{3}{4} y

to the right side

d = \frac{y - 2}{2} - \frac{3}{4} y

- 10 k + 1 = 40 - 7 k

- 6 = - 2 + s

x, 3 x + 4 y = 18

x, y (x - y) + 2 z (x - 3 z) = 5 yz

- \frac{x}{1.6} - 1.8 = - 3.3

What is the answer to solvefor d,sqrt(1/2 y-1)= 3/4 y+d ?
The answer to solvefor d,sqrt(1/2 y-1)= 3/4 y+d is d=sqrt((y-2)/2)-3/4 y