What are the solutions to the equation -2x^2+16x-24=0 ?

The solutions to the equation -2x^2+16x-24=0 are x=2,x=6

Find the zeros of -2x^2+16x-24=0

The zeros of -2x^2+16x-24=0 are x=2,x=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} + 16 x - 24 = 0

x = 2, x = 6

Solution steps

- 2 x^{2} + 16 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 2 ) ( - 24 )}{2 ( - 2 )}

1 6^{2} - 4 (- 2) (- 24) = 8

x_{1, 2} = \frac{- 16 \pm 8}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 16 + 8}{2 ( - 2 )}, x_{2} = \frac{- 16 - 8}{2 ( - 2 )}

x = \frac{- 16 + 8}{2 ( - 2 )} : 2

x = \frac{- 16 - 8}{2 ( - 2 )} : 6

The solutions to the quadratic equation are:

x = 2, x = 6

\frac{7}{8} - \frac{3}{8}

\frac{3}{\frac{2}{5}}

4 x^{2} + 2 x + 4 = 0

∣ 5 x - 4 ∣ + 2 \geq 9

- \frac{1 ( 2 ( - 1 ) + 1 )}{- 1 ( - 1 + 2 ( 1 ) )}

What are the solutions to the equation -2x^2+16x-24=0 ?
The solutions to the equation -2x^2+16x-24=0 are x=2,x=6
Find the zeros of -2x^2+16x-24=0
The zeros of -2x^2+16x-24=0 are x=2,x=6