What is the answer to solvefor c,ln(x/y)=1+cy ?

The answer to solvefor c,ln(x/y)=1+cy is c=(ln(x/y)-1)/y ;\quad y\ne 0

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solvefor c,ln(x/y)=1+cy

solve for

c, ln (\frac{x}{y}) = 1 + cy

c = \frac{ln ( \frac{x}{y} ) - 1}{y}; y \neq = 0

Solution steps

ln (\frac{x}{y}) = 1 + cy

Switch sides

1 + cy = ln (\frac{x}{y})

Move

1

to the right side

cy = ln (\frac{x}{y}) - 1

Divide both sides by

y; y \neq = 0

c = \frac{ln ( \frac{x}{y} ) - 1}{y}; y \neq = 0

2 am x - 4 a = 5 m x + m - 2 a x

3 x - 66 + 8 x = - 7 x + 13 + x + 23

x, 5 x = y - 4

11 x - 3 = 4 x - 31

1 + y = 1

What is the answer to solvefor c,ln(x/y)=1+cy ?
The answer to solvefor c,ln(x/y)=1+cy is c=(ln(x/y)-1)/y ;\quad y\ne 0