What are the solutions to the equation 3x-5x^2=9 ?

The solutions to the equation 3x-5x^2=9 are x= 3/10-i(3sqrt(19))/(10),x= 3/10+i(3sqrt(19))/(10)

Find the zeros of 3x-5x^2=9

The zeros of 3x-5x^2=9 are x= 3/10-i(3sqrt(19))/(10),x= 3/10+i(3sqrt(19))/(10)

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3 x - 5 x^{2} = 9

x = \frac{3}{10} - i \frac{3 19}{10}, x = \frac{3}{10} + i \frac{3 19}{10}

Solution steps

3 x - 5 x^{2} = 9

Move

9

to the left side

3 x - 5 x^{2} - 9 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 5 x^{2} + 3 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 5 ) ( - 9 )}{2 ( - 5 )}

Simplify

3^{2} - 4 (- 5) (- 9) : 319 i

x_{1, 2} = \frac{- 3 \pm 3 19 i}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 3 + 3 19 i}{2 ( - 5 )}, x_{2} = \frac{- 3 - 3 19 i}{2 ( - 5 )}

x = \frac{- 3 + 3 19 i}{2 ( - 5 )} : \frac{3}{10} - i \frac{3 19}{10}

x = \frac{- 3 - 3 19 i}{2 ( - 5 )} : \frac{3}{10} + i \frac{3 19}{10}

The solutions to the quadratic equation are:

x = \frac{3}{10} - i \frac{3 19}{10}, x = \frac{3}{10} + i \frac{3 19}{10}

x < 7 or x < 8

12 a^{3} + 8 a

(x - 3)^{2} + 5 = 21

- (x + y)

x y - 3 y + x - 3

What are the solutions to the equation 3x-5x^2=9 ?
The solutions to the equation 3x-5x^2=9 are x= 3/10-i(3sqrt(19))/(10),x= 3/10+i(3sqrt(19))/(10)
Find the zeros of 3x-5x^2=9
The zeros of 3x-5x^2=9 are x= 3/10-i(3sqrt(19))/(10),x= 3/10+i(3sqrt(19))/(10)