What are the solutions to the equation x^2-8x+65=0 ?

The solutions to the equation x^2-8x+65=0 are x=4+7i,x=4-7i

Find the zeros of x^2-8x+65=0

The zeros of x^2-8x+65=0 are x=4+7i,x=4-7i

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x^{2} - 8 x + 65 = 0

x = 4 + 7 i, x = 4 - 7 i

Solution steps

x^{2} - 8 x + 65 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 65}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 65 : 14 i

x_{1, 2} = \frac{- ( - 8 ) \pm 14 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 14 i}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 14 i}{2 \cdot 1}

x = \frac{- ( - 8 ) + 14 i}{2 \cdot 1} : 4 + 7 i

x = \frac{- ( - 8 ) - 14 i}{2 \cdot 1} : 4 - 7 i

The solutions to the quadratic equation are:

x = 4 + 7 i, x = 4 - 7 i

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\frac{3}{4} x^{2} + 8 x + 20 = 0

- 10 r + 2 (3 r - 7) > - 3 r + 3 - 7

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What are the solutions to the equation x^2-8x+65=0 ?
The solutions to the equation x^2-8x+65=0 are x=4+7i,x=4-7i
Find the zeros of x^2-8x+65=0
The zeros of x^2-8x+65=0 are x=4+7i,x=4-7i