What are the solutions to the equation 3/4 x^2+8x+20=0 ?

The solutions to the equation 3/4 x^2+8x+20=0 are x=-4,x=-20/3

Find the zeros of 3/4 x^2+8x+20=0

The zeros of 3/4 x^2+8x+20=0 are x=-4,x=-20/3

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\frac{3}{4} x^{2} + 8 x + 20 = 0

x = - 4, x = - \frac{20}{3}

Decimal Notation

x = - 4, x = - 6.66666 \dots

Solution steps

\frac{3}{4} x^{2} + 8 x + 20 = 0

Multiply both sides by

4

3 x^{2} + 32 x + 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 \cdot 3 \cdot 80}{2 \cdot 3}

3 2^{2} - 4 \cdot 3 \cdot 80 = 8

x_{1, 2} = \frac{- 32 \pm 8}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 32 + 8}{2 \cdot 3}, x_{2} = \frac{- 32 - 8}{2 \cdot 3}

x = \frac{- 32 + 8}{2 \cdot 3} : - 4

x = \frac{- 32 - 8}{2 \cdot 3} : - \frac{20}{3}

The solutions to the quadratic equation are:

x = - 4, x = - \frac{20}{3}

- 10 r + 2 (3 r - 7) > - 3 r + 3 - 7

∣ 3 - 5 z ∣ + 6 < 14

k^{2} - 22 k - 23

5 i (2 + 3 i) + 4 (6 - 2 i)

2 x^{2} = - 6 x - 4

What are the solutions to the equation 3/4 x^2+8x+20=0 ?
The solutions to the equation 3/4 x^2+8x+20=0 are x=-4,x=-20/3
Find the zeros of 3/4 x^2+8x+20=0
The zeros of 3/4 x^2+8x+20=0 are x=-4,x=-20/3