What is 5i(2+3i)+4(6-2i) ?

The solution to 5i(2+3i)+4(6-2i) is 9+2i

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simplify 5i(2+3i)+4(6-2i)

simplify

5 i (2 + 3 i) + 4 (6 - 2 i)

9 + 2 i

Solution steps

5 i (2 + 3 i) + 4 (6 - 2 i)

Expand

5 i (2 + 3 i) : 10 i - 15

= 10 i - 15 + 4 (6 - 2 i)

Expand

4 (6 - 2 i) : 24 - 8 i

= 10 i - 15 + 24 - 8 i

Group like terms

= 10 i - 8 i - 15 + 24

Add similar elements:

10 i - 8 i = 2 i

= 2 i - 15 + 24

Add the numbers:

- 15 + 24 = 9

= 2 i + 9

Rewrite in standard complex form:

9 + 2 i

= 9 + 2 i

2 x^{2} = - 6 x - 4

- 6 (5 - x) < 30

\frac{2 ! 8 !}{4 ! 6 !}

(2 s^{3} t^{- 1}) (\frac{1}{4} s^{6}) (16 t^{4})

5 [4 - 2 (3 - w)] = 8 - 4 (2 w - 1)