What is the answer to solvefor B,F(B-g^3)=2 ?

The answer to solvefor B,F(B-g^3)=2 is B= 2/F+g^3;\quad F\ne 0

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solvefor B,F(B-g^3)=2

solve for

B, F (B - g^{3}) = 2

B = \frac{2}{F} + g^{3}; F \neq = 0

Solution steps

F (B - g^{3}) = 2

Divide both sides by

F; F \neq = 0

B - g^{3} = \frac{2}{F}; F \neq = 0

Move

g^{3}

to the right side

B = \frac{2}{F} + g^{3}; F \neq = 0

- z - 6 - 7 z = 9 (- z - 2) + 6

3 x^{2} + 3 - 6 x = 3 (x - 1)^{2}

x, - 5 x + 4 y = 3

p, A = p + p r t

- 15 + 5 = 2 x

What is the answer to solvefor B,F(B-g^3)=2 ?
The answer to solvefor B,F(B-g^3)=2 is B= 2/F+g^3;\quad F\ne 0