What are the solutions to the equation 5x^2-6x=-8 ?

The solutions to the equation 5x^2-6x=-8 are x= 3/5+i(sqrt(31))/5 ,x= 3/5-i(sqrt(31))/5

Find the zeros of 5x^2-6x=-8

The zeros of 5x^2-6x=-8 are x= 3/5+i(sqrt(31))/5 ,x= 3/5-i(sqrt(31))/5

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5 x^{2} - 6 x = - 8

x = \frac{3}{5} + i \frac{31}{5}, x = \frac{3}{5} - i \frac{31}{5}

Solution steps

5 x^{2} - 6 x = - 8

Move

8

to the left side

5 x^{2} - 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 5 \cdot 8}{2 \cdot 5}

Simplify

(- 6)^{2} - 4 \cdot 5 \cdot 8 : 231 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 31 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 31 i}{2 \cdot 5}, x_{2} = \frac{- ( - 6 ) - 2 31 i}{2 \cdot 5}

x = \frac{- ( - 6 ) + 2 31 i}{2 \cdot 5} : \frac{3}{5} + i \frac{31}{5}

x = \frac{- ( - 6 ) - 2 31 i}{2 \cdot 5} : \frac{3}{5} - i \frac{31}{5}

The solutions to the quadratic equation are:

x = \frac{3}{5} + i \frac{31}{5}, x = \frac{3}{5} - i \frac{31}{5}

(8 - 15 i) + (- 3 + 2 i)

x^{3} + 9 x^{2} - 52 x

\frac{5 x - 3}{2} - 2 = 1

15.09 + 59.62 t - 15.86 t^{2} = 60

7 x^{2} - 43 x + 6 = 0

What are the solutions to the equation 5x^2-6x=-8 ?
The solutions to the equation 5x^2-6x=-8 are x= 3/5+i(sqrt(31))/5 ,x= 3/5-i(sqrt(31))/5
Find the zeros of 5x^2-6x=-8
The zeros of 5x^2-6x=-8 are x= 3/5+i(sqrt(31))/5 ,x= 3/5-i(sqrt(31))/5