What is the answer to solvefor x,x^2+4y=(x+6)(x-2) ?

The answer to solvefor x,x^2+4y=(x+6)(x-2) is x=y+3

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solvefor x,x^2+4y=(x+6)(x-2)

solve for

x, x^{2} + 4 y = (x + 6) (x - 2)

x = y + 3

Solution steps

x^{2} + 4 y = (x + 6) (x - 2)

Expand

(x + 6) (x - 2) : x^{2} + 4 x - 12

x^{2} + 4 y = x^{2} + 4 x - 12

Move

4 y

to the right side

x^{2} = x^{2} + 4 x - 12 - 4 y

Subtract

x^{2} + 4 x

from both sides

x^{2} - (x^{2} + 4 x) = x^{2} + 4 x - 12 - 4 y - (x^{2} + 4 x)

Simplify

- 4 x = - 12 - 4 y

Divide both sides by

- 4

x = y + 3

y = 6^{2}

\frac{2 x - 3}{3} + \frac{5 - x}{2} = 3

3 = x - 3 + 5 x

a, f = a x^{2} + b x

b, y = b x^{n}

What is the answer to solvefor x,x^2+4y=(x+6)(x-2) ?
The answer to solvefor x,x^2+4y=(x+6)(x-2) is x=y+3