What is the answer to (x-5)^2=x(x-8)+11 ?

The answer to (x-5)^2=x(x-8)+11 is x=7

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(x-5)^2=x(x-8)+11

(x - 5)^{2} = x (x - 8) + 11

x = 7

Solution steps

(x - 5)^{2} = x (x - 8) + 11

Expand

x (x - 8) : x^{2} - 8 x

x^{2} - 10 x + 25 = x^{2} - 8 x + 11

Expand

(x - 5)^{2} : x^{2} - 10 x + 25

x^{2} - 10 x + 25 = x^{2} - 8 x + 11

Move

25

to the right side

x^{2} - 10 x = x^{2} - 8 x - 14

Subtract

x^{2} - 8 x

from both sides

x^{2} - 10 x - (x^{2} - 8 x) = x^{2} - 8 x - 14 - (x^{2} - 8 x)

Simplify

- 2 x = - 14

Divide both sides by

- 2

x = 7

- 9 T - 21 = 24

x, \frac{x}{2} - \frac{y}{3} = 1

4 + \frac{k}{2} = - 3

x, - 6 x + 4 y = 20

x, y - 1 = \frac{2}{3} (x + 3)

What is the answer to (x-5)^2=x(x-8)+11 ?
The answer to (x-5)^2=x(x-8)+11 is x=7
Solve for x: (x-5)^2=x(x-8)+11
The solution is x=7