What are the solutions to the equation x^2-2x+37=0 ?

The solutions to the equation x^2-2x+37=0 are x=1+6i,x=1-6i

Find the zeros of x^2-2x+37=0

The zeros of x^2-2x+37=0 are x=1+6i,x=1-6i

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x^{2} - 2 x + 37 = 0

x = 1 + 6 i, x = 1 - 6 i

Solution steps

x^{2} - 2 x + 37 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 37}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 37 : 12 i

x_{1, 2} = \frac{- ( - 2 ) \pm 12 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 12 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 12 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 12 i}{2 \cdot 1} : 1 + 6 i

x = \frac{- ( - 2 ) - 12 i}{2 \cdot 1} : 1 - 6 i

The solutions to the quadratic equation are:

x = 1 + 6 i, x = 1 - 6 i

7.63242994 8^{3}

\frac{3}{4} x + 3 = \frac{5}{8}

(y + 4)^{2} = 4

2 x^{2} + 5 x + 5 = 0

(2 x + 1)^{2} + 7 (2 x + 1) + 12

What are the solutions to the equation x^2-2x+37=0 ?
The solutions to the equation x^2-2x+37=0 are x=1+6i,x=1-6i
Find the zeros of x^2-2x+37=0
The zeros of x^2-2x+37=0 are x=1+6i,x=1-6i