What are the solutions to the equation x^2-9x+20=0 ?

The solutions to the equation x^2-9x+20=0 are x=5,x=4

Find the zeros of x^2-9x+20=0

The zeros of x^2-9x+20=0 are x=5,x=4

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x^{2} - 9 x + 20 = 0

x = 5, x = 4

Solution steps

x^{2} - 9 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 20 = 1

x_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 1}

x = \frac{- ( - 9 ) + 1}{2 \cdot 1} : 5

x = \frac{- ( - 9 ) - 1}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

x = 5, x = 4

(2 x^{0} y^{2})^{- 3} \cdot 2 y x^{3}

3 x^{2} + 11 x - 4 < 0

2 (x - 2) = 10

x^{3} - x^{2} + 5 x + 7

What are the solutions to the equation x^2-9x+20=0 ?
The solutions to the equation x^2-9x+20=0 are x=5,x=4
Find the zeros of x^2-9x+20=0
The zeros of x^2-9x+20=0 are x=5,x=4