What are the solutions to the equation x^2+x=20 ?

The solutions to the equation x^2+x=20 are x=4,x=-5

Find the zeros of x^2+x=20

The zeros of x^2+x=20 are x=4,x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + x = 20

x = 4, x = - 5

Solution steps

x^{2} + x = 20

Move

20

to the left side

x^{2} + x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 20) = 9

x_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 9}{2 \cdot 1}, x_{2} = \frac{- 1 - 9}{2 \cdot 1}

x = \frac{- 1 + 9}{2 \cdot 1} : 4

x = \frac{- 1 - 9}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 4, x = - 5

\frac{1}{1 + \frac{1}{2}}

\frac{y}{2 x} + \frac{1}{3 x}

t^{3} < 9 t^{2}

(\frac{x - 1}{2})^{2}

5 x^{2} - 7 x = 0

What are the solutions to the equation x^2+x=20 ?
The solutions to the equation x^2+x=20 are x=4,x=-5
Find the zeros of x^2+x=20
The zeros of x^2+x=20 are x=4,x=-5