What is the answer to (x+3)^2=(x+2)^2+17 ?

The answer to (x+3)^2=(x+2)^2+17 is x=6

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(x+3)^2=(x+2)^2+17

(x + 3)^{2} = (x + 2)^{2} + 17

x = 6

Solution steps

(x + 3)^{2} = (x + 2)^{2} + 17

Expand

(x + 3)^{2} : x^{2} + 6 x + 9

Expand

(x + 2)^{2} + 17 : x^{2} + 4 x + 21

x^{2} + 6 x + 9 = x^{2} + 4 x + 21

Move

9

to the right side

x^{2} + 6 x = x^{2} + 4 x + 12

Subtract

x^{2} + 4 x

from both sides

x^{2} + 6 x - (x^{2} + 4 x) = x^{2} + 4 x + 12 - (x^{2} + 4 x)

Simplify

2 x = 12

Divide both sides by

2

x = 6

\frac{1}{2} (6 x - 8) = \frac{1}{3} (12 x - 9)

x, 8 + 3 y = - 2 x

5 j - 9 j + 3 = - 34

(\frac{3}{2} y + 2 - 3 y) + (- 3 + 4 y - \frac{2}{6} y) = 12

\frac{- x - 21}{3} = 6 x + 2

What is the answer to (x+3)^2=(x+2)^2+17 ?
The answer to (x+3)^2=(x+2)^2+17 is x=6
Solve for x: (x+3)^2=(x+2)^2+17
The solution is x=6