What is (3x^9)/(6y^{-2)}*(12y^{-3})/(4x) ?

The solution to (3x^9)/(6y^{-2)}*(12y^{-3})/(4x) is (3x^8)/(2y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (3x^9)/(6y^{-2)}*(12y^{-3})/(4x)

simplify

\frac{3 x ^{9}}{6 y ^{- 2}} \cdot \frac{12 y ^{- 3}}{4 x}

\frac{3 x ^{8}}{2 y}

Solution steps

\frac{3 x ^{9}}{6 y ^{- 2}} \cdot \frac{12 y ^{- 3}}{4 x}

Cancel

\frac{3 x ^{9}}{6 y ^{- 2}} : \frac{x ^{9} y ^{2}}{2}

= \frac{x ^{9} y ^{2}}{2} \cdot \frac{12 y ^{- 3}}{4 x}

Cancel

\frac{12 y ^{- 3}}{4 x} : \frac{3}{y ^{3} x}

= \frac{x ^{9} y ^{2}}{2} \cdot \frac{3}{y ^{3} x}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{x ^{9} y ^{2} \cdot 3}{2 y ^{3} x}

Simplify

\frac{x ^{9}}{x} : x^{8}

= \frac{x ^{8} y ^{2} \cdot 3}{2 y ^{3}}

Simplify

\frac{y ^{2}}{y ^{3}} : \frac{1}{y}

= \frac{x ^{8} \cdot 3}{2 y}

= \frac{3 x ^{8}}{2 y}

w^{2} - 4 = 0

\frac{4}{10} x - 4 x + \frac{6}{5} = \frac{4}{5}

15 n^{2} - 27 n - 6

\frac{x}{- \frac{1}{6}} = \frac{6}{7}

x m - 3 m y - 2 x y + 6 y^{2}

What is (3x^9)/(6y^{-2)}*(12y^{-3})/(4x) ?
The solution to (3x^9)/(6y^{-2)}*(12y^{-3})/(4x) is (3x^8)/(2y)