What is (x-3)^3(x+2)^2(x-6)^2>0 ?

The solution to (x-3)^3(x+2)^2(x-6)^2>0 is 3 6

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(x-3)^3(x+2)^2(x-6)^2>0

(x - 3)^{3} (x + 2)^{2} (x - 6)^{2} > 0

3 < x < 6 or x > 6

Interval Notation

(3, 6) \cup (6, \infty)

Solution steps

(x - 3)^{3} (x + 2)^{2} (x - 6)^{2} > 0

Identify the intervals

3 < x < 6 or x > 6

y^{3} + 64

\frac{2}{2 - 5}

e^{l n (9)}

x^{2} - 17 = - 1

- 4 a^{- 2} b^{- 2}

What is (x-3)^3(x+2)^2(x-6)^2>0 ?
The solution to (x-3)^3(x+2)^2(x-6)^2>0 is 3<x<6\lor x>6