What are the solutions to the equation x^2-17=-1 ?

The solutions to the equation x^2-17=-1 are x=4,x=-4

Find the zeros of x^2-17=-1

The zeros of x^2-17=-1 are x=4,x=-4

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x^{2} - 17 = - 1

x = 4, x = - 4

Solution steps

x^{2} - 17 = - 1

Move

17

to the right side

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

- 4 a^{- 2} b^{- 2}

5 w^{2} + 10 w = 40

- \frac{7}{6} \geq \frac{1}{2} x - \frac{5}{3}

\frac{5}{6} + \frac{2}{9}

3 x^{2} - 18 x + 15 \leq 0

What are the solutions to the equation x^2-17=-1 ?
The solutions to the equation x^2-17=-1 are x=4,x=-4
Find the zeros of x^2-17=-1
The zeros of x^2-17=-1 are x=4,x=-4