What are the solutions to the equation 5w^2+10w=40 ?

The solutions to the equation 5w^2+10w=40 are w=2,w=-4

Find the zeros of 5w^2+10w=40

The zeros of 5w^2+10w=40 are w=2,w=-4

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5 w^{2} + 10 w = 40

w = 2, w = - 4

Solution steps

5 w^{2} + 10 w = 40

Move

40

to the left side

5 w^{2} + 10 w - 40 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 5 ( - 40 )}{2 \cdot 5}

1 0^{2} - 4 \cdot 5 (- 40) = 30

w_{1, 2} = \frac{- 10 \pm 30}{2 \cdot 5}

Separate the solutions

w_{1} = \frac{- 10 + 30}{2 \cdot 5}, w_{2} = \frac{- 10 - 30}{2 \cdot 5}

w = \frac{- 10 + 30}{2 \cdot 5} : 2

w = \frac{- 10 - 30}{2 \cdot 5} : - 4

The solutions to the quadratic equation are:

w = 2, w = - 4

- \frac{7}{6} \geq \frac{1}{2} x - \frac{5}{3}

\frac{5}{6} + \frac{2}{9}

3 x^{2} - 18 x + 15 \leq 0

627

(b + 7) (b - 6) = (b + 2) (b - 9)

What are the solutions to the equation 5w^2+10w=40 ?
The solutions to the equation 5w^2+10w=40 are w=2,w=-4
Find the zeros of 5w^2+10w=40
The zeros of 5w^2+10w=40 are w=2,w=-4