What are the solutions to the equation y^2-14y=-47 ?

The solutions to the equation y^2-14y=-47 are y=7+sqrt(2),y=7-sqrt(2)

Find the zeros of y^2-14y=-47

The zeros of y^2-14y=-47 are y=7+sqrt(2),y=7-sqrt(2)

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y^{2} - 14 y = - 47

y = 7 + 2, y = 7 - 2

Decimal Notation

y = 8.41421 \dots, y = 5.58578 \dots

Solution steps

y^{2} - 14 y = - 47

Move

47

to the left side

y^{2} - 14 y + 47 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 47}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 47 = 22

y_{1, 2} = \frac{- ( - 14 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 14 ) + 2 2}{2 \cdot 1}, y_{2} = \frac{- ( - 14 ) - 2 2}{2 \cdot 1}

y = \frac{- ( - 14 ) + 2 2}{2 \cdot 1} : 7 + 2

y = \frac{- ( - 14 ) - 2 2}{2 \cdot 1} : 7 - 2

The solutions to the quadratic equation are:

y = 7 + 2, y = 7 - 2

\frac{7 a ^{2}}{15 b ^{2}} \times \frac{6 b}{5 a}

- 6 x \leq 42

9 x^{2} + 2 x - 1 = 0

5 x^{2} - 19 x + 12

\frac{5 ( m ^{- 2} ) ^{3}}{20 m ^{9}}

What are the solutions to the equation y^2-14y=-47 ?
The solutions to the equation y^2-14y=-47 are y=7+sqrt(2),y=7-sqrt(2)
Find the zeros of y^2-14y=-47
The zeros of y^2-14y=-47 are y=7+sqrt(2),y=7-sqrt(2)