What are the solutions to the equation a^2-9a-36=0 ?

The solutions to the equation a^2-9a-36=0 are a=12,a=-3

Find the zeros of a^2-9a-36=0

The zeros of a^2-9a-36=0 are a=12,a=-3

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a^{2} - 9 a - 36 = 0

a = 12, a = - 3

Solution steps

a^{2} - 9 a - 36 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 36) = 15

a_{1, 2} = \frac{- ( - 9 ) \pm 15}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 9 ) + 15}{2 \cdot 1}, a_{2} = \frac{- ( - 9 ) - 15}{2 \cdot 1}

a = \frac{- ( - 9 ) + 15}{2 \cdot 1} : 12

a = \frac{- ( - 9 ) - 15}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

a = 12, a = - 3

- \frac{1}{2} x = - 7

(8 x - 1) (2 x + 1) = 3 x

\frac{2 ! 4 !}{3 !}

- 2 x < 10

4 a^{2} - 16 a = - 15

What are the solutions to the equation a^2-9a-36=0 ?
The solutions to the equation a^2-9a-36=0 are a=12,a=-3
Find the zeros of a^2-9a-36=0
The zeros of a^2-9a-36=0 are a=12,a=-3