What is (8+i)/(8-i) ?

The solution to (8+i)/(8-i) is 63/65+16/65 i

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simplify (8+i)/(8-i)

simplify

\frac{8 + i}{8 - i}

\frac{63}{65} + \frac{16}{65} i

Solution steps

\frac{8 + i}{8 - i}

Multiply by the conjugate

\frac{8 + i}{8 + i}

= \frac{( 8 + i ) ( 8 + i )}{( 8 - i ) ( 8 + i )}

Simplify

\frac{( 8 + i ) ( 8 + i )}{( 8 - i ) ( 8 + i )} : \frac{16 i + 63}{65}

= \frac{16 i + 63}{65}

Rewrite in standard complex form:

\frac{63}{65} + \frac{16}{65} i

= \frac{63}{65} + \frac{16}{65} i

21 x^{2} + 41 x + 10

\frac{( 1 + 2 i )}{( 3 - 4 i )}

\frac{\frac{2}{3}}{\frac{1}{2}}

\frac{x ^{- 4}}{x ^{- 6}}

3 w^{2} + w - 1 = 0