What are the solutions to the equation 4x^2+8x=0 ?

The solutions to the equation 4x^2+8x=0 are x=0,x=-2

Find the zeros of 4x^2+8x=0

The zeros of 4x^2+8x=0 are x=0,x=-2

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4 x^{2} + 8 x = 0

x = 0, x = - 2

Solution steps

4 x^{2} + 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

8^{2} - 4 \cdot 4 \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 8}{2 \cdot 4}, x_{2} = \frac{- 8 - 8}{2 \cdot 4}

x = \frac{- 8 + 8}{2 \cdot 4} : 0

x = \frac{- 8 - 8}{2 \cdot 4} : - 2

The solutions to the quadratic equation are:

x = 0, x = - 2

16 y^{8}

12 x^{3} - 4 x^{2}

(8 x + 1) (x - 7) \geq (2 x - 3) (4 x + 5)

10 m^{2} + 52 m = - 10

\frac{2 x + 2}{3} + \frac{5 x + x}{6} = \frac{15 + 2 x}{12}

What are the solutions to the equation 4x^2+8x=0 ?
The solutions to the equation 4x^2+8x=0 are x=0,x=-2
Find the zeros of 4x^2+8x=0
The zeros of 4x^2+8x=0 are x=0,x=-2