What is the answer to y(y-3)-2y(y+5)+6(y^2-3y-7)=5(1-y)^2+2 ?

The answer to y(y-3)-2y(y+5)+6(y^2-3y-7)=5(1-y)^2+2 is y=-7/3

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y(y-3)-2y(y+5)+6(y^2-3y-7)=5(1-y)^2+2

y (y - 3) - 2 y (y + 5) + 6 (y^{2} - 3 y - 7) = 5 (1 - y)^{2} + 2

y = - \frac{7}{3}

Decimal Notation

y = - 2.33333 \dots

Solution steps

y (y - 3) - 2 y (y + 5) + 6 (y^{2} - 3 y - 7) = 5 (1 - y)^{2} + 2

Expand

y (y - 3) - 2 y (y + 5) + 6 (y^{2} - 3 y - 7) : 5 y^{2} - 31 y - 42

Expand

5 (1 - y)^{2} + 2 : 5 y^{2} - 10 y + 7

5 y^{2} - 31 y - 42 = 5 y^{2} - 10 y + 7

Move

42

to the right side

5 y^{2} - 31 y = 5 y^{2} - 10 y + 49

Subtract

5 y^{2} - 10 y

from both sides

5 y^{2} - 31 y - (5 y^{2} - 10 y) = 5 y^{2} - 10 y + 49 - (5 y^{2} - 10 y)

Simplify

- 21 y = 49

Divide both sides by

- 21

y = - \frac{7}{3}

\frac{a}{15} = 5

c, c y^{2} = x^{2} + y

x, 4 x - y = - 5

28 = 8 x + 12 - 7 x

x, 4 x + 3 y = 29

What is the answer to y(y-3)-2y(y+5)+6(y^2-3y-7)=5(1-y)^2+2 ?
The answer to y(y-3)-2y(y+5)+6(y^2-3y-7)=5(1-y)^2+2 is y=-7/3
Solve for y: y(y-3)-2y(y+5)+6(y^2-3y-7)=5(1-y)^2+2
The solution is y=-7/3