What is the answer to solvefor c,cy^2=x^2+y ?

The answer to solvefor c,cy^2=x^2+y is c=(x^2+y)/(y^2);\quad y\ne 0

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solvefor c,cy^2=x^2+y

solve for

c, c y^{2} = x^{2} + y

c = \frac{x ^{2} + y}{y ^{2}}; y \neq = 0

Solution steps

c y^{2} = x^{2} + y

Divide both sides by

y^{2}; y \neq = 0

c = \frac{x ^{2} + y}{y ^{2}}; y \neq = 0

x, 4 x - y = - 5

28 = 8 x + 12 - 7 x

x, 4 x + 3 y = 29

x^{2} - 8 x + 10 = (x - 2)^{2}

y, 3 x - 4 y = 6

What is the answer to solvefor c,cy^2=x^2+y ?
The answer to solvefor c,cy^2=x^2+y is c=(x^2+y)/(y^2);\quad y\ne 0