What are the solutions to the equation 4m^2+m+6=2 ?

The solutions to the equation 4m^2+m+6=2 are m=-1/8+i(3sqrt(7))/8 ,m=-1/8-i(3sqrt(7))/8

Find the zeros of 4m^2+m+6=2

The zeros of 4m^2+m+6=2 are m=-1/8+i(3sqrt(7))/8 ,m=-1/8-i(3sqrt(7))/8

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4 m^{2} + m + 6 = 2

m = - \frac{1}{8} + i \frac{3 7}{8}, m = - \frac{1}{8} - i \frac{3 7}{8}

Solution steps

4 m^{2} + m + 6 = 2

Move

2

to the left side

4 m^{2} + m + 4 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

Simplify

1^{2} - 4 \cdot 4 \cdot 4 : 37 i

m_{1, 2} = \frac{- 1 \pm 3 7 i}{2 \cdot 4}

Separate the solutions

m_{1} = \frac{- 1 + 3 7 i}{2 \cdot 4}, m_{2} = \frac{- 1 - 3 7 i}{2 \cdot 4}

m = \frac{- 1 + 3 7 i}{2 \cdot 4} : - \frac{1}{8} + i \frac{3 7}{8}

m = \frac{- 1 - 3 7 i}{2 \cdot 4} : - \frac{1}{8} - i \frac{3 7}{8}

The solutions to the quadratic equation are:

m = - \frac{1}{8} + i \frac{3 7}{8}, m = - \frac{1}{8} - i \frac{3 7}{8}

(- 26 - x) (- 44 - x) - 40 \cdot 40 = 0

x^{5} - 6 x^{4} - 12 x^{3} + 82 x^{2} - 45 x + 300

\frac{∣ m ∣}{5} = 3

\frac{π \cdot 9 \cdot 1 0 ^{6}}{2} \cdot 0. 5^{4} \cdot \frac{3.0 1 ^{4}}{1 0 ^{12}}

\frac{3}{5} + 3

What are the solutions to the equation 4m^2+m+6=2 ?
The solutions to the equation 4m^2+m+6=2 are m=-1/8+i(3sqrt(7))/8 ,m=-1/8-i(3sqrt(7))/8
Find the zeros of 4m^2+m+6=2
The zeros of 4m^2+m+6=2 are m=-1/8+i(3sqrt(7))/8 ,m=-1/8-i(3sqrt(7))/8