What is (2n)/2-(n-1)/(n-4) ?

The solution to (2n)/2-(n-1)/(n-4) is (n^2-5n+1)/(n-4)

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simplify (2n)/2-(n-1)/(n-4)

simplify

\frac{2 n}{2} - \frac{n - 1}{n - 4}

\frac{n ^{2} - 5 n + 1}{n - 4}

Solution steps

\frac{2 n}{2} - \frac{n - 1}{n - 4}

Least Common Multiplier of

2, n - 4 : 2 (n - 4)

Adjust Fractions based on the LCM

= \frac{2 n ( n - 4 )}{2 ( n - 4 )} - \frac{( n - 1 ) \cdot 2}{2 ( n - 4 )}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{2 n ( n - 4 ) - ( n - 1 ) \cdot 2}{2 ( n - 4 )}

Simplify

2 n (n - 4) - (n - 1) \cdot 2 : 2 n^{2} - 10 n + 2

= \frac{2 n ^{2} - 10 n + 2}{2 ( n - 4 )}

Cancel

\frac{2 n ^{2} - 10 n + 2}{2 ( n - 4 )} : \frac{n ^{2} - 5 n + 1}{n - 4}

= \frac{n ^{2} - 5 n + 1}{n - 4}

0.8726 \cdot \frac{1 0 ^{3}}{101325}

5 \leq \frac{1}{3} x + 7 < 6

2 (v + 2) = 10

2500

\frac{1}{x + 1} + \frac{1}{x - 2} \geq 0

What is (2n)/2-(n-1)/(n-4) ?
The solution to (2n)/2-(n-1)/(n-4) is (n^2-5n+1)/(n-4)