What is 1/(x+1)+1/(x-2)>= 0 ?

The solution to 1/(x+1)+1/(x-2)>= 0 is -1 2

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1/(x+1)+1/(x-2)>= 0

\frac{1}{x + 1} + \frac{1}{x - 2} \geq 0

- 1 < x \leq \frac{1}{2} or x > 2

Interval Notation

(- 1, \frac{1}{2}] \cup (2, \infty)

Decimal Notation

- 1 < x \leq 0.5 or x > 2

Solution steps

\frac{1}{x + 1} + \frac{1}{x - 2} \geq 0

Rewrite in standard form

\frac{2 x - 1}{( x + 1 ) ( x - 2 )} \geq 0

Identify the intervals

- 1 < x \leq \frac{1}{2} or x > 2

4 q^{2} - 5 q = 3 q^{2} - 8 q + 10

5 (x - 8) = 30

\frac{1}{x} \leq 1

x^{2} + 2 x y + y^{2} - 4

\frac{1}{3} (x + 2) = \frac{2}{3} x + 4

What is 1/(x+1)+1/(x-2)>= 0 ?
The solution to 1/(x+1)+1/(x-2)>= 0 is -1<x<= 1/2 \lor x>2