What are the solutions to the equation (3x+2)^2+64=0 ?

The solutions to the equation (3x+2)^2+64=0 are x=-2/3+i 8/3 ,x=-2/3-i 8/3

Find the zeros of (3x+2)^2+64=0

The zeros of (3x+2)^2+64=0 are x=-2/3+i 8/3 ,x=-2/3-i 8/3

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(3 x + 2)^{2} + 64 = 0

x = - \frac{2}{3} + i \frac{8}{3}, x = - \frac{2}{3} - i \frac{8}{3}

Solution steps

(3 x + 2)^{2} + 64 = 0

Move

64

to the right side

(3 x + 2)^{2} = - 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 2 = - 64 : x = - \frac{2}{3} + i \frac{8}{3}

Solve

3 x + 2 = - - 64 : x = - \frac{2}{3} - i \frac{8}{3}

The solutions to the quadratic equation are:

x = - \frac{2}{3} + i \frac{8}{3}, x = - \frac{2}{3} - i \frac{8}{3}

\frac{1 + \frac{x}{y}}{\frac{x}{y}}

- x^{2} + 4 x = 0

6 p^{2} - 5 p - 11 = 5 p^{2}

x x^{\frac{1}{2}}

x < - 10 and x < 10

What are the solutions to the equation (3x+2)^2+64=0 ?
The solutions to the equation (3x+2)^2+64=0 are x=-2/3+i 8/3 ,x=-2/3-i 8/3
Find the zeros of (3x+2)^2+64=0
The zeros of (3x+2)^2+64=0 are x=-2/3+i 8/3 ,x=-2/3-i 8/3