What are the solutions to the equation 12x=-2x^2+61x+330 ?

The solutions to the equation 12x=-2x^2+61x+330 are x=-11/2 ,x=30

Find the zeros of 12x=-2x^2+61x+330

The zeros of 12x=-2x^2+61x+330 are x=-11/2 ,x=30

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12 x = - 2 x^{2} + 61 x + 330

x = - \frac{11}{2}, x = 30

Decimal Notation

x = - 5.5, x = 30

Solution steps

12 x = - 2 x^{2} + 61 x + 330

Switch sides

- 2 x^{2} + 61 x + 330 = 12 x

Move

12 x

to the left side

- 2 x^{2} + 49 x + 330 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 49 \pm 4 9 ^{2} - 4 ( - 2 ) \cdot 330}{2 ( - 2 )}

4 9^{2} - 4 (- 2) \cdot 330 = 71

x_{1, 2} = \frac{- 49 \pm 71}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 49 + 71}{2 ( - 2 )}, x_{2} = \frac{- 49 - 71}{2 ( - 2 )}

x = \frac{- 49 + 71}{2 ( - 2 )} : - \frac{11}{2}

x = \frac{- 49 - 71}{2 ( - 2 )} : 30

The solutions to the quadratic equation are:

x = - \frac{11}{2}, x = 30

\frac{5}{3} - 4

2 y - 10 y^{2} = 0

x^{2} + 12 x + 35 = 0

25 y^{2} - 64

(4.54 - 3.1) \cdot 0.5 \cdot 0.3

What are the solutions to the equation 12x=-2x^2+61x+330 ?
The solutions to the equation 12x=-2x^2+61x+330 are x=-11/2 ,x=30
Find the zeros of 12x=-2x^2+61x+330
The zeros of 12x=-2x^2+61x+330 are x=-11/2 ,x=30