What are the solutions to the equation x^2+12x+35=0 ?

The solutions to the equation x^2+12x+35=0 are x=-5,x=-7

Find the zeros of x^2+12x+35=0

The zeros of x^2+12x+35=0 are x=-5,x=-7

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x^{2} + 12 x + 35 = 0

x = - 5, x = - 7

Solution steps

x^{2} + 12 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 35 = 2

x_{1, 2} = \frac{- 12 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2}{2 \cdot 1}, x_{2} = \frac{- 12 - 2}{2 \cdot 1}

x = \frac{- 12 + 2}{2 \cdot 1} : - 5

x = \frac{- 12 - 2}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = - 5, x = - 7

25 y^{2} - 64

(4.54 - 3.1) \cdot 0.5 \cdot 0.3

x^{2} = - 63

\frac{( x - 3 ) ( x + 7 )}{x - 4} \leq 0

What are the solutions to the equation x^2+12x+35=0 ?
The solutions to the equation x^2+12x+35=0 are x=-5,x=-7
Find the zeros of x^2+12x+35=0
The zeros of x^2+12x+35=0 are x=-5,x=-7