What are the solutions to the equation 4x^2-6x+2=0 ?

The solutions to the equation 4x^2-6x+2=0 are x=1,x= 1/2

Find the zeros of 4x^2-6x+2=0

The zeros of 4x^2-6x+2=0 are x=1,x= 1/2

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4 x^{2} - 6 x + 2 = 0

x = 1, x = \frac{1}{2}

Solution steps

4 x^{2} - 6 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 4 \cdot 2}{2 \cdot 4}

(- 6)^{2} - 4 \cdot 4 \cdot 2 = 2

x_{1, 2} = \frac{- ( - 6 ) \pm 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2}{2 \cdot 4}, x_{2} = \frac{- ( - 6 ) - 2}{2 \cdot 4}

x = \frac{- ( - 6 ) + 2}{2 \cdot 4} : 1

x = \frac{- ( - 6 ) - 2}{2 \cdot 4} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 1, x = \frac{1}{2}

4 x^{2} + 4 x = - 13

10 + 2 p > 4

100 x^{3} y

3 x - 8 \geq 5 x + 7

18 + 1

What are the solutions to the equation 4x^2-6x+2=0 ?
The solutions to the equation 4x^2-6x+2=0 are x=1,x= 1/2
Find the zeros of 4x^2-6x+2=0
The zeros of 4x^2-6x+2=0 are x=1,x= 1/2