What are the solutions to the equation 7x^2-12x+16=0 ?

The solutions to the equation 7x^2-12x+16=0 are x= 6/7+i(2sqrt(19))/7 ,x= 6/7-i(2sqrt(19))/7

Find the zeros of 7x^2-12x+16=0

The zeros of 7x^2-12x+16=0 are x= 6/7+i(2sqrt(19))/7 ,x= 6/7-i(2sqrt(19))/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7 x^{2} - 12 x + 16 = 0

x = \frac{6}{7} + i \frac{2 19}{7}, x = \frac{6}{7} - i \frac{2 19}{7}

Solution steps

7 x^{2} - 12 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 7 \cdot 16}{2 \cdot 7}

Simplify

(- 12)^{2} - 4 \cdot 7 \cdot 16 : 419 i

x_{1, 2} = \frac{- ( - 12 ) \pm 4 19 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 19 i}{2 \cdot 7}, x_{2} = \frac{- ( - 12 ) - 4 19 i}{2 \cdot 7}

x = \frac{- ( - 12 ) + 4 19 i}{2 \cdot 7} : \frac{6}{7} + i \frac{2 19}{7}

x = \frac{- ( - 12 ) - 4 19 i}{2 \cdot 7} : \frac{6}{7} - i \frac{2 19}{7}

The solutions to the quadratic equation are:

x = \frac{6}{7} + i \frac{2 19}{7}, x = \frac{6}{7} - i \frac{2 19}{7}

\frac{5}{3} x + \frac{3}{4} > \frac{2}{5}

10 x^{2} - 11 x y - 6 y^{2}

5 x + 41 = 2 x + 14

\frac{2 x ^{3} y}{3 z ^{4}} \cdot \frac{6 x z ^{5}}{10 y ^{5}}

- 109 > \frac{p}{- 10} - 97

What are the solutions to the equation 7x^2-12x+16=0 ?
The solutions to the equation 7x^2-12x+16=0 are x= 6/7+i(2sqrt(19))/7 ,x= 6/7-i(2sqrt(19))/7
Find the zeros of 7x^2-12x+16=0
The zeros of 7x^2-12x+16=0 are x= 6/7+i(2sqrt(19))/7 ,x= 6/7-i(2sqrt(19))/7