What are the solutions to the equation 15x^2+4x-4=0 ?

The solutions to the equation 15x^2+4x-4=0 are x= 2/5 ,x=-2/3

Find the zeros of 15x^2+4x-4=0

The zeros of 15x^2+4x-4=0 are x= 2/5 ,x=-2/3

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15 x^{2} + 4 x - 4 = 0

x = \frac{2}{5}, x = - \frac{2}{3}

Solution steps

15 x^{2} + 4 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 15 ( - 4 )}{2 \cdot 15}

4^{2} - 4 \cdot 15 (- 4) = 16

x_{1, 2} = \frac{- 4 \pm 16}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 4 + 16}{2 \cdot 15}, x_{2} = \frac{- 4 - 16}{2 \cdot 15}

x = \frac{- 4 + 16}{2 \cdot 15} : \frac{2}{5}

x = \frac{- 4 - 16}{2 \cdot 15} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = - \frac{2}{3}

\frac{x}{6} + 5 = \frac{1}{3} - x

\frac{4}{3} - 3 x < - 15

5 x^{2} - 5 x - 30 = 0

x^{2} - 12 x - 28

3 x^{2} + 12 x + 81 = 15

What are the solutions to the equation 15x^2+4x-4=0 ?
The solutions to the equation 15x^2+4x-4=0 are x= 2/5 ,x=-2/3
Find the zeros of 15x^2+4x-4=0
The zeros of 15x^2+4x-4=0 are x= 2/5 ,x=-2/3