What are the solutions to the equation (x+1)^2-3x*(x+2)=3 ?

The solutions to the equation (x+1)^2-3x*(x+2)=3 are x=-1

Find the zeros of (x+1)^2-3x*(x+2)=3

The zeros of (x+1)^2-3x*(x+2)=3 are x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 1)^{2} - 3 x \cdot (x + 2) = 3

x = - 1

Solution steps

(x + 1)^{2} - 3 x (x + 2) = 3

Expand

(x + 1)^{2} - 3 x (x + 2) : - 2 x^{2} - 4 x + 1

- 2 x^{2} - 4 x + 1 = 3

Move

3

to the left side

- 2 x^{2} - 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 2 ) ( - 2 )}{2 ( - 2 )}

(- 4)^{2} - 4 (- 2) (- 2) = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 ( - 2 )}

x = \frac{- ( - 4 )}{2 ( - 2 )}

\frac{- ( - 4 )}{2 ( - 2 )} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

\frac{6 m ^{4} n ^{7}}{12 m ^{5} n ^{- 8}}

3 + (- 4)

8^{- \frac{1}{2}} \cdot 8^{\frac{7}{6}}

2 x^{2} - 6 x + 2

6 p^{2} - 8 p = - 3

What are the solutions to the equation (x+1)^2-3x*(x+2)=3 ?
The solutions to the equation (x+1)^2-3x*(x+2)=3 are x=-1
Find the zeros of (x+1)^2-3x*(x+2)=3
The zeros of (x+1)^2-3x*(x+2)=3 are x=-1