What are the solutions to the equation (2-x)(x-1)=0 ?

The solutions to the equation (2-x)(x-1)=0 are x=2,x=1

Find the zeros of (2-x)(x-1)=0

The zeros of (2-x)(x-1)=0 are x=2,x=1

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(2 - x) (x - 1) = 0

x = 2, x = 1

Solution steps

(2 - x) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 - x = 0 or x - 1 = 0

Solve

2 - x = 0 : x = 2

Solve

x - 1 = 0 : x = 1

The solutions to the quadratic equation are:

x = 2, x = 1

- x^{2} - x + 4 = 0

7 (t - 3) > 4 (t - 8)

v^{2} + 10 v + 25

0.554 \cdot \frac{145.8}{178.5}

What are the solutions to the equation (2-x)(x-1)=0 ?
The solutions to the equation (2-x)(x-1)=0 are x=2,x=1
Find the zeros of (2-x)(x-1)=0
The zeros of (2-x)(x-1)=0 are x=2,x=1