What are the solutions to the equation r^2+2r+1=0 ?

The solutions to the equation r^2+2r+1=0 are r=-1

Find the zeros of r^2+2r+1=0

The zeros of r^2+2r+1=0 are r=-1

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r^{2} + 2 r + 1 = 0

r = - 1

Solution steps

r^{2} + 2 r + 1 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

r_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

r = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

r = - 1

The solution to the quadratic equation is:

r = - 1

- 15 k > - 120

6 x^{2} - 18 x - 240

x^{\frac{1}{2}} \cdot x^{\frac{1}{2}}

8 x^{2} - 5 x - 4 = 0

0.6

What are the solutions to the equation r^2+2r+1=0 ?
The solutions to the equation r^2+2r+1=0 are r=-1
Find the zeros of r^2+2r+1=0
The zeros of r^2+2r+1=0 are r=-1