What is the answer to (x+1)/3+(x+3)/6 =2 ?

The answer to (x+1)/3+(x+3)/6 =2 is x= 7/3

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(x+1)/3+(x+3)/6 =2

\frac{x + 1}{3} + \frac{x + 3}{6} = 2

x = \frac{7}{3}

Decimal Notation

x = 2.33333 \dots

Solution steps

\frac{x + 1}{3} + \frac{x + 3}{6} = 2

Multiply by LCM

2 (x + 1) + x + 3 = 12

Expand

2 (x + 1) + x + 3 : 3 x + 5

3 x + 5 = 12

Move

5

to the right side

3 x = 7

Divide both sides by

3

x = \frac{7}{3}

x, y = 7 x - 2 y

19 = 9 t

\frac{2}{9} (0^{3} + 2)^{\frac{3}{2}} + C = - \frac{1}{3}

5 - 2 x = - 4 x + 9

\frac{1}{8} (5 y + 64) = \frac{1}{4} (20 + 2 y)

What is the answer to (x+1)/3+(x+3)/6 =2 ?
The answer to (x+1)/3+(x+3)/6 =2 is x= 7/3
Solve for x: (x+1)/3+(x+3)/6 =2
The solution is x= 7/3