What is the answer to solvefor x,mx+(m-1)y=1 ?

The answer to solvefor x,mx+(m-1)y=1 is x=(1-y(m-1))/m ;\quad m\ne 0

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solvefor x,mx+(m-1)y=1

solve for

x, m x + (m - 1) y = 1

x = \frac{1 - y ( m - 1 )}{m}; m \neq = 0

Solution steps

m x + (m - 1) y = 1

Move

(m - 1) y

to the right side

m x = 1 - (m - 1) y

Divide both sides by

m; m \neq = 0

x = \frac{1 - y ( m - 1 )}{m}; m \neq = 0

lo g_{8} (25) = x lo g_{8} (5)

5 x + 25 = 0

- \frac{1}{3} (4 - 2 e) - 4 = e - \frac{1}{2}

y, 3 x - 2 y = - 2

\frac{x}{4} + \frac{x + 1}{3} + \frac{x - 2}{6} = x - 3

What is the answer to solvefor x,mx+(m-1)y=1 ?
The answer to solvefor x,mx+(m-1)y=1 is x=(1-y(m-1))/m ;\quad m\ne 0