What is the answer to log_{1/243}(1/9)=-2y ?

The answer to log_{1/243}(1/9)=-2y is y=-1/5

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log_{1/243}(1/9)=-2y

lo g_{\frac{1}{243}} (\frac{1}{9}) = - 2 y

y = - \frac{1}{5}

Decimal Notation

y = - 0.2

Solution steps

lo g_{\frac{1}{243}} (\frac{1}{9}) = - 2 y

Switch sides

- 2 y = lo g_{\frac{1}{243}} (\frac{1}{9})

Divide both sides by

- 2

y = - \frac{1}{5}

t, d = v t

3 (2 a - x) + a x = a^{2} + 25

2 (x - 1) - 3 = 5 x

10 = 15 - 5 x

- 7 (8 + 5 y) + 8 y = 25

What is the answer to log_{1/243}(1/9)=-2y ?
The answer to log_{1/243}(1/9)=-2y is y=-1/5
Solve for y: log_{1/243}(1/9)=-2y
The solution is y=-1/5