What is the answer to 2-(2x-1)/3+(1-3x)/7 =7-2x ?

The answer to 2-(2x-1)/3+(1-3x)/7 =7-2x is x=5

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2-(2x-1)/3+(1-3x)/7 =7-2x

2 - \frac{2 x - 1}{3} + \frac{1 - 3 x}{7} = 7 - 2 x

x = 5

Solution steps

2 - \frac{2 x - 1}{3} + \frac{1 - 3 x}{7} = 7 - 2 x

Multiply by LCM

42 - 7 (2 x - 1) + 3 (- 3 x + 1) = 147 - 42 x

Expand

42 - 7 (2 x - 1) + 3 (- 3 x + 1) : - 23 x + 52

- 23 x + 52 = 147 - 42 x

Move

52

to the right side

- 23 x = - 42 x + 95

Move

42 x

to the left side

19 x = 95

Divide both sides by

19

x = 5

\frac{a - 3 b}{a ^{2} - 3 ab}

\frac{1.01 \cdot 1 0 ^{- 14}}{2.2 \cdot 1 0 ^{- 8}}

2 = m^{2} + 4

q^{4} + 5 q^{3} + 8 q + 40

4 x^{2} + 15 x^{3} + 4 x y - 2 x^{3}

What is the answer to 2-(2x-1)/3+(1-3x)/7 =7-2x ?
The answer to 2-(2x-1)/3+(1-3x)/7 =7-2x is x=5
Solve for x: 2-(2x-1)/3+(1-3x)/7 =7-2x
The solution is x=5