What is (35x^3yz^2)/(21x^2y^3z) ?

The solution to (35x^3yz^2)/(21x^2y^3z) is (5xz)/(3y^2)

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simplify (35x^3yz^2)/(21x^2y^3z)

simplify

\frac{35 x ^{3} y z ^{2}}{21 x ^{2} y ^{3} z}

\frac{5 x z}{3 y ^{2}}

Solution steps

\frac{35 x ^{3} y z ^{2}}{21 x ^{2} y ^{3} z}

Factor the number:

35 = 7 \cdot 5

= \frac{7 \cdot 5 x ^{3} y z ^{2}}{21 x ^{2} y ^{3} z}

Factor the number:

21 = 7 \cdot 3

= \frac{7 \cdot 5 x ^{3} y z ^{2}}{7 \cdot 3 x ^{2} y ^{3} z}

Cancel the common factor:

7

= \frac{5 x ^{3} y z ^{2}}{3 x ^{2} y ^{3} z}

Simplify

\frac{x ^{3}}{x ^{2}} : x

= \frac{5 x y z ^{2}}{3 y ^{3} z}

Simplify

\frac{z ^{2}}{z} : z

= \frac{5 x yz}{3 y ^{3}}

Simplify

\frac{y}{y ^{3}} : \frac{1}{y ^{2}}

= \frac{5 x z}{3 y ^{2}}

\frac{- 6 ( - 4 ) + ( - 2 ) ^{3}}{- 4}

8 x^{2} = - 26 x

x^{2} + (x + 7)^{2} = (2 x - 7)^{2}

3 x^{2} + 13 x + 4

8 x \geq - 16

What is (35x^3yz^2)/(21x^2y^3z) ?
The solution to (35x^3yz^2)/(21x^2y^3z) is (5xz)/(3y^2)