What is the answer to 7x+2(3x-2(x+3))=5 ?

The answer to 7x+2(3x-2(x+3))=5 is x= 17/9

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7x+2(3x-2(x+3))=5

7 x + 2 (3 x - 2 (x + 3)) = 5

x = \frac{17}{9}

Decimal Notation

x = 1.88888 \dots

Solution steps

7 x + 2 (3 x - 2 (x + 3)) = 5

Expand

7 x + 2 (3 x - 2 (x + 3)) : 9 x - 12

9 x - 12 = 5

Move

12

to the right side

9 x = 17

Divide both sides by

9

x = \frac{17}{9}

x, 6 x - 2 y = 18

t, t (x) = \frac{x ^{2} - 3 x - 18}{x - 8}

\frac{5}{8} - \frac{2}{3} x = \frac{1}{6} x + 0.25

x - 3 = 1 + 7 x

\frac{x + 5}{6} = \frac{4 x + 8}{10}

What is the answer to 7x+2(3x-2(x+3))=5 ?
The answer to 7x+2(3x-2(x+3))=5 is x= 17/9
Solve for x: 7x+2(3x-2(x+3))=5
The solution is x= 17/9