What is the general solution for solvefor c,1+e^{-x}cos(x)=0 ?

The general solution for solvefor c,1+e^{-x}cos(x)=0 is True for all c;\quad 1+e^{-x}cos(x)=0

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solvefor c,1+e^{-x}cos(x)=0

solve for

c, 1 + e^{- x} cos (x) = 0

True for all c; 1 + e^{- x} cos (x) = 0

Solution steps

1 + e^{- x} cos (x) = 0

Both sides are equal

True for all c; 1 + e^{- x} cos (x) = 0

x, z = 6 - 2 x - 3 y

\frac{x}{2} - \frac{x + 14}{3} + \frac{x + 7}{9} = 0

x, 2 x y = 3

x, 2 x y = 5

\frac{x + 4 i}{i} - \frac{x + 4 i}{2 i} + \frac{x}{- 4 i} + \frac{x}{4} = 0

What is the general solution for solvefor c,1+e^{-x}cos(x)=0 ?
The general solution for solvefor c,1+e^{-x}cos(x)=0 is True for all c;\quad 1+e^{-x}cos(x)=0