What are the solutions to the equation y^2-3y=9 ?

The solutions to the equation y^2-3y=9 are y=(3+3sqrt(5))/2 ,y=(3-3sqrt(5))/2

Find the zeros of y^2-3y=9

The zeros of y^2-3y=9 are y=(3+3sqrt(5))/2 ,y=(3-3sqrt(5))/2

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y^{2} - 3 y = 9

y = \frac{3 + 3 5}{2}, y = \frac{3 - 3 5}{2}

Decimal Notation

y = 4.85410 \dots, y = - 1.85410 \dots

Solution steps

y^{2} - 3 y = 9

Move

9

to the left side

y^{2} - 3 y - 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 9) = 35

y_{1, 2} = \frac{- ( - 3 ) \pm 3 5}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 3 ) + 3 5}{2 \cdot 1}, y_{2} = \frac{- ( - 3 ) - 3 5}{2 \cdot 1}

y = \frac{- ( - 3 ) + 3 5}{2 \cdot 1} : \frac{3 + 3 5}{2}

y = \frac{- ( - 3 ) - 3 5}{2 \cdot 1} : \frac{3 - 3 5}{2}

The solutions to the quadratic equation are:

y = \frac{3 + 3 5}{2}, y = \frac{3 - 3 5}{2}

3 x^{2} + 6 x + 1 = 0

\frac{\frac{3}{2}}{2}

a^{6} + b^{9}

2 m - [(m - n) - (m + n)]

- \frac{1}{2}

What are the solutions to the equation y^2-3y=9 ?
The solutions to the equation y^2-3y=9 are y=(3+3sqrt(5))/2 ,y=(3-3sqrt(5))/2
Find the zeros of y^2-3y=9
The zeros of y^2-3y=9 are y=(3+3sqrt(5))/2 ,y=(3-3sqrt(5))/2