What is the answer to solvefor y,x^2+4xy=1200 ?

The answer to solvefor y,x^2+4xy=1200 is y=(1200-x^2)/(4x);\quad x\ne 0

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solvefor y,x^2+4xy=1200

solve for

y, x^{2} + 4 x y = 1200

y = \frac{1200 - x ^{2}}{4 x}; x \neq = 0

Solution steps

x^{2} + 4 x y = 1200

Move

x^{2}

to the right side

4 x y = 1200 - x^{2}

Divide both sides by

4 x; x \neq = 0

y = \frac{1200 - x ^{2}}{4 x}; x \neq = 0

- 5 x + 10 = - 2 x - 14

\frac{4}{20} = \frac{1}{5}

(x - 3) = \frac{( x + 15 )}{4}

A, 2 s - 9 = A (s + 4) + B (s - 5)

y, x = \frac{4 + 5 y}{2}

What is the answer to solvefor y,x^2+4xy=1200 ?
The answer to solvefor y,x^2+4xy=1200 is y=(1200-x^2)/(4x);\quad x\ne 0