What is the answer to solvefor A,2s-9=A(s+4)+B(s-5) ?

The answer to solvefor A,2s-9=A(s+4)+B(s-5) is A=(2s-9-B(s-5))/(s+4);\quad s\ne-4

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solvefor A,2s-9=A(s+4)+B(s-5)

solve for

A, 2 s - 9 = A (s + 4) + B (s - 5)

A = \frac{2 s - 9 - B ( s - 5 )}{s + 4}; s \neq = - 4

Solution steps

2 s - 9 = A (s + 4) + B (s - 5)

Switch sides

A (s + 4) + B (s - 5) = 2 s - 9

Move

B (s - 5)

to the right side

A (s + 4) = 2 s - 9 - B (s - 5)

Divide both sides by

s + 4; s \neq = - 4

A = \frac{2 s - 9 - B ( s - 5 )}{s + 4}; s \neq = - 4

y, x = \frac{4 + 5 y}{2}

8 y - 6 = 5 y + 12

x + 18 = - 13

\frac{x + 1}{3} + \frac{x - 6}{2} = \frac{3 x - 1}{6}

\frac{3}{5} x - 2 = \frac{2}{3} x + 3

What is the answer to solvefor A,2s-9=A(s+4)+B(s-5) ?
The answer to solvefor A,2s-9=A(s+4)+B(s-5) is A=(2s-9-B(s-5))/(s+4);\quad s\ne-4